11x^2-300x-695=0

Solution for 11x^2-300x-695=0 equation:

11x^2-300x-695=0

a = 11; b = -300; c = -695;
Δ = b2-4ac
Δ = -3002-4·11·(-695)
Δ = 120580
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{120580}=\sqrt{4*30145}=\sqrt{4}*\sqrt{30145}=2\sqrt{30145}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-300)-2\sqrt{30145}}{2*11}=\frac{300-2\sqrt{30145}}{22}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-300)+2\sqrt{30145}}{2*11}=\frac{300+2\sqrt{30145}}{22}
$